Reply to comment

Fun with fuses solution

December 2009

 

Fun with fuses

Lit fuse

You are given two fuses, each of which burns for exactly one minute. However, since the fuses are not of uniform thickness, they do not burn at a uniform rate along their lengths. How can you use the two fuses to measure 45 seconds?

Solution

The trick to solving this puzzle is to consider lighting the fuses at both ends. We know they don't burn evenly, but by lighting a fuse at both ends it will burn twice as fast, and burn itself out in half the time.

So to start off with light fuse A at one end, and light fuse B at both ends. Fuse B will burn out after 30 seconds. Fuse A has now been burning for 30 seconds and so has 30 seconds left to burn, so at this point light the other end of Fuse A. Fuse A is now burning twice as fast, and will extinguish after a further 15 seconds (half the time it had left to burn). Therefore Fuse A has burned for 45 seconds in total.

 

Back to main puzzle page

Reply

  • Web page addresses and e-mail addresses turn into links automatically.
  • Allowed HTML tags: <a> <em> <strong> <cite> <code> <ul> <ol> <li> <dl> <dt> <dd>
  • Lines and paragraphs break automatically.

More information about formatting options

To prevent automated spam submissions leave this field empty.
By submitting this form, you accept the Mollom privacy policy.