Permalink Submitted by Anonymous on November 27, 2012

Suppose my strategy is to double at 2/3 + epsilon where epsilon < (4/5 - 2/3) instead of at your suggested value of 2/3.

Suppose you have just doubled at 2/3. Eventually the win chance will reach either 2/3 + epsilon or 1/2. In the former case we then are in the same position both having doubled and at the same win chance. In the second case we both have 1/2 win chance but I have cube access and you have given the cube to the opponent. I am in the better situation. Thus my strategy is better.

## No, it is 4/5.

Suppose my strategy is to double at 2/3 + epsilon where epsilon < (4/5 - 2/3) instead of at your suggested value of 2/3.

Suppose you have just doubled at 2/3. Eventually the win chance will reach either 2/3 + epsilon or 1/2. In the former case we then are in the same position both having doubled and at the same win chance. In the second case we both have 1/2 win chance but I have cube access and you have given the cube to the opponent. I am in the better situation. Thus my strategy is better.

Bob Koca

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