X is blue. Y is red. Z is white. Since, the option 3 suggests that Z is not blue than it could be red or white.

As option 2 is wrong as per the question's condition; therefore Y is red. Resulting Z as White as the only option. And hence, X is blue.

## COUNTERLOGIC PUZZLE SOLUTION

X is blue.

Y is red.

Z is white.

Since, the option 3 suggests that

Z is not blue than it could be red or white.

As option 2 is wrong as per the question's condition; therefore Y is red.

Resulting Z as White as the only option.

And hence, X is blue.