The question without the accompanying diagram could also mean to roll the small circle within the larger one. If this is done you actually lose a rotation. The answer then is 3!
The easiest way to calculate the rotations is to use the path taken by the centre of the small circle.
If r = radius of small circle; r = radius of path outside and r = radius of path inside the large circle then:-
Rotations outside = (2 x pi x r)/(2 x pi x r) = (2 x pi x 5)/(2 x pi x 1) = 5/1 = 5.
Rotations inside = (2 x pi x r)/(2 x pi x r) = (2 x pi x 3)/(2 x pi x 1) = 3/1 = 3.