Outer space: Blowin' in the wind

Share this page
Submitted by plusadmin on 1 December, 2007
December 2007

Finding the maximal efficiency

We want to calculate the maximum value of windmill efficiency $P/P_0$. Write $y$ for $P/P_0$ and $x$ for $V/U$. We get

  \[ y = \frac{1}{2}(1-x^2)(1+x). \]    
Differentiating we get
  \[ dy/dx = \frac{1}{2}(1 - 2x - 3x^2). \]    
The maximum occurs when $dy/dx = 0$, in other words when
  \[ 3x^2 + 2x - 1 = 0. \]    
This happens for $x_0=1/3$ and $x_1=-1$. Discounting the negative solution we get a maximal efficiency of
  \[ 1/2(1-x_0^2)(1+x_0) = 16/27. \]    

Back to main article

Read more about...
outerspace