Add new comment

Permalink Submitted by Anonymous (not verified) on 25 August, 2010

If the outcomes of two risky events are independent and their probabilities of causing death are p1 and p2, then the probability of at least one of them leading to death is p1 + p2 - p1*p1. So, using micromorbs m1 = p1*10^6 and m2 = p2*10^6 leads to the following micromorb value for two independent risky events

m1 + m2 - m1*m2*10^-6

Jim
http://jvwhite.com

About text formats

Filtered HTML

  • Web page addresses and email addresses turn into links automatically.
  • Allowed HTML tags: <a href hreflang> <em> <strong> <cite> <code> <ul type> <ol start type> <li> <dl> <dt> <dd>
  • Lines and paragraphs break automatically.
  • Maths in a minute

    Want facts and want them fast? Our Maths in a minute series explores key mathematical concepts in just a few words.

  • Chocolate and mayonnaise
    chocolate

    What do chocolate and mayonnaise have in common? It's maths! Find out how in this podcast featuring engineer Valerie Pinfield.

  • From clicks to chords
    icon

    Is it possible to write unique music with the limited quantity of notes and chords available? We ask musician Oli Freke!

  • The lungs of the Earth

    How can maths help to understand the Southern Ocean, a vital component of the Earth's climate system?

  • SBIDER Presents: Shining a light on COVID modelling
    icon

    Was the mathematical modelling projecting the course of the pandemic too pessimistic, or were the projections justified? Matt Keeling tells our colleagues from SBIDER about the COVID models that fed into public policy.

  • Mathematical snapshots: Daniel Kreuter

    PhD student Daniel Kreuter tells us about his work on the BloodCounts! project, which uses maths to make optimal use of the billions of blood tests performed every year around the globe.