Add new comment


I am confused by:

Thus, setting $a = m^2, b = 2mn, c= n^2$ and $d=(m+n)^2$ gives us a Pythagorean quadruple.

I think it should actually be

Thus, setting $a^2 = m^2, b^2 = 2mn, c^2= n^2$ and $d^2=(m+n)^2$ gives us a Pythagorean quadruple.

It should be noted that $b^2= 2 m n$ does not give us an integer $b$ unless $2 m n$ is a perfect square. In the following set of equations $ d=m+n$ and not $d=(m+n)^2$.

The section on extending to longer sequences is very interesting.

Filtered HTML

  • Web page addresses and email addresses turn into links automatically.
  • Allowed HTML tags: <a href hreflang> <em> <strong> <cite> <code> <ul type> <ol start type> <li> <dl> <dt> <dd>
  • Lines and paragraphs break automatically.
  • Want facts and want them fast? Our Maths in a minute series explores key mathematical concepts in just a few words.