Equal averages Comment How to derive the formula? Enumerate the first 15 possibilities: N: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 NS: 0 1 0 1 2 1 2 3 2 3 4 3 4 5 4 NS is number of sets See the pattern: 1: N: 1 4 7 10 13 NS: 0 1 2 3 4 2: N: 2 5 8 11 14 NS: 1 2 3 4 5 3: N: 3 6 9 12 15 NS: 0 1 2 3 4 or 1: N mod(3) = 1 -> NS = (N - 1) / 3 2: N mod(3) = 2 -> NS = (N + 1) / 3 3: N mod(3) = 0 -> NS = (N - 3) / 3 and 1: (N – 1) / 3 = (N - 3 + 2 * 1) / 3 2: (N + 1) / 3 = (N - 3 + 2 * 2) / 3 3: (N – 3) / 3 = (N - 3 + 2 * 0) / 3 All together: NS = (N - 3 + 2 * N(mod(3)) / 3 I verified the result for N = 1 up to 10000. Everything OK. Hub. Reply
How to derive the formula?
Enumerate the first 15 possibilities:
N: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
NS: 0 1 0 1 2 1 2 3 2 3 4 3 4 5 4
NS is number of sets
See the pattern:
1: N: 1 4 7 10 13
NS: 0 1 2 3 4
2: N: 2 5 8 11 14
NS: 1 2 3 4 5
3: N: 3 6 9 12 15
NS: 0 1 2 3 4
or
1: N mod(3) = 1 -> NS = (N - 1) / 3
2: N mod(3) = 2 -> NS = (N + 1) / 3
3: N mod(3) = 0 -> NS = (N - 3) / 3
and
1: (N – 1) / 3 = (N - 3 + 2 * 1) / 3
2: (N + 1) / 3 = (N - 3 + 2 * 2) / 3
3: (N – 3) / 3 = (N - 3 + 2 * 0) / 3
All together: NS = (N - 3 + 2 * N(mod(3)) / 3
I verified the result for N = 1 up to 10000. Everything OK.
Hub.