It's a divide and conquer one Comment It's a divide and conquer one. I liked the one here below, with a little twist. --------- You have 9 balls. 8 of them weigh the same, but one of them weighs heavier than the other 8. How can we find the heaviest weighted ball in no more than 2 operations? Reply
It's a divide and conquer one. I liked the one here below, with a little twist.
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You have 9 balls. 8 of them weigh the same, but one of them weighs heavier than the other 8.
How can we find the heaviest weighted ball in no more than 2 operations?