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You said...
"If a/bc = a/(bc), then a/bc = a/b/c
Which seems nonsensical to me."

In fact that is completely correct - just put some numbers in...
In the same way that distributing a minus over a bracketed term changes any + to a -, distributing a ÷ over any bracketed term changes a x to a ÷.
This is a well-known property in Maths which is covered when teaching multiplying and dividing fractions.
Someone once asked me "what is a/b/c/d?". Easy, a/bcd

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