In the previous article we introduced Schrödinger's equation and its solution, the wave function, which contains all the information there is to know about a quantum system. Now it's time to see the equation in action, using a very simple physical system as an example. We'll also look at another weird phenomenon called quantum tunneling. (If you'd like to skip the maths you can go straight to the third article in this series which explores the interpretation of the wave function.)
The particle in a box.
Suppose you have a particle bouncing back and forth between two walls in a box. Assume that the particle moves in one dimension only, along the -axis, between vertical, impenetrable walls at and There are no forces acting on the particle inside the box, so its potential energy is zero here: for . Infinitely large forces push the particle back when it hits a wall: the potential energy is infinite for and
Since in this example the potential energy does not depend on time we can use the time-independent one-dimensional Schrödinger equation within the box. Recalling that in the box we therefore have
where is the mass of the particle, is its total energy and is Planck’s constant.
A solution to equation (1) is a function which when differentiated satisfies the equation. Any solution to equation (1) will take the form
where and are constants.
Now is related to the probability of finding the particle at position and time We know that the particle can never be outside the box (in the region where or ) because it would need an infinite amount of energy to get there. This means that for and And since is continuous at the boundary of the box, we deduce that is also equal to zero at and
The first condition, at , means that
so we can ignore the cosine term in (2) and our equation becomes
The second condition, at , means that
so either or the sine term is zero. The former would imply that is zero everywhere — this clearly can’t be the case as we know that the particle is somewhere in the box. So we deduce that
Now if and only if is a multiple of , so we have
In other words
for a positive integer.
This tells us that the energy of the particle can only have discrete values
The number corresponding to the energy level is called the quantum number of .
The quantum number corresponds to zero energy — but it also gives a wave function which is zero everywhere in the box, which would mean the particle cannot be anywhere in the box. Thus, the quantum number is also ruled out, so the permissible energy levels are
Wave-particle duality is a central concept in quantum mechanics.
The fact that the energy spectrum is discrete, ie that not all energies are permitted, and in particular that zero energy is not permitted, are results you don't get out of classical mechanics — in fact, they fly in the face of conventional wisdom, which holds that quantities such as energy should vary continuously: "nature does not make jumps" according to Gottfried Leibniz. Classical physics also tells us that the lowest energy state of a system (also called the ground state or the vacuum) should have zero energy. But these strange quantum results tally with the experimental observations of quantum systems, for example the discrete energy spectrum of the hydrogen atom.
The value of the constant B can be found by normalising the wave function. Recall that
Now is a complex number, which can also be written as
The modulus of this complex number is therefore
by the familiar trigonometric identity. Therefore we have
Now recall that is the probability density function for finding the particle at location at time In other words, the probability that the particle is somewhere in the box is given by
Since we know for sure that the particle is somewhere in the box we have
Substituting our expression for from equation (3) we have
Using the fact that
we can work out that
The particle in a box: the position of the particle is shown on the x-axis and the energy on the y-axis. The permitted energy levels for the first four quantum numbers are shown as horizontal dotted lines. The wavefunctions are shown superimposed on the diagram at the corresponding energies. Image: Papa November.
Substituting the possible values for from (4) we get infinitely many wave functions (one for each quantum number, ie permitted energy level):
This gives us another surprising result: for any value of that is bigger than 1 we can find a value of that lies within the box for which if for some integer , then and
Since is the probability density of finding the particle at the point , this means that there are places in the box where the particle can never be found!
Thus we’ve seen how Schrödinger’s equation produces some very weird results that contradict our classical intuition. So why do we not see things like the discrete energy levels in macroscopic objects like billiard balls? The lowest permitted energy occurs for the quantum number and
Planck’s constant is very small, So for a large object, and will be comparatively huge. This means that will be so incredibly small that an object with energy becomes indistinguishable from one at rest. This is why in the macroscopic world a zero energy level does appear to be possible.
Now let’s compute the difference between two adjacent energy levels and for a quantum number :
As the mass and the size of the box get large, this difference tends to zero. So for large objects the permitted energy levels are so close together that it’s impossible to distinguish them from the energy levels that are not permitted — the energy level appears to vary continuously.
Quantum tunneling: The vertical axis shows the potential energy of the particle, which is equal to V0 for x greater than 0 and less than L and zero elsewhere.
Now let’s change our set-up a little. Let’s still assume that our particle moves along the -axis. But this time suppose that the potential energy is zero for and for but non-zero between and . So for This is a potential barrier: classical physics tells us that if the particle is moving right along the negative -axis towards 0, it can only penetrate the region between and if its energy is greater than
It’s a bit like a ball of mass rolling along and encountering a hill of height : if it has enough energy to move to the top of the hill, then its potential energy there will be where is acceleration due to gravity. If its energy is less than the ball will never make it to the top. Only in our example the hill has a vertical slope because the potential energy jumps discontinuously between 0 and at and , and it is flat on the top because the potential energy is constant for
It turns out that in quantum mechanics the particle can make it to the top, and even the other side, of the "potential hill" even if its energy is less than . We won’t go into the details here but solving Schrödinger’s equation (assuming ) with suitable boundary conditions gives a wave function that is non-zero on the entire -axis. This means that a particle coming from the left actually has a non-zero probability of being found inside the barrier and even to the right of it. There is a small but non-zero probability that the particle will tunnel through the barrier to the other side, even though in classical terms it does not have enough energy to do so. As you would expect, this probability becomes smaller the thicker the barrier, that is, the larger the value of .
Generally the term quantum tunneling refers to any situation in which a particle overcomes a potential barrier that it should not be able to overcome according to classical physics. Quantum tunneling does occur in nature, for example in when uranium decays to thorium in a form of radioactive decay known as alpha decay. Here the atomic nucleus emits an alpha particle (which consists of two protons and two neutrons and is structurally identical to a helium nucleus). According to classical physics, the process of emitting the particle should be impossible, as it requires more energy than the atom has available. It's through quantum tunneling that the atom accomplishes the feat.
The big question raised by all this mathematics is what Schrödinger's equation tells us about physical reality. How should we interpret its solution, the wave function? This is what we'll explore in the third article.
Read the final article Schrödinger's equation, what does it mean?
About the author
Marianne Freiberger is Editor of Plus. She would like to thank Jeremy Butterfield, a philosopher of physics, Nazim Bouatta, a Postdoctoral Fellow in Foundations of Physics, and Tony Short, a Royal Society Research Fellow in Foundations of Quantum Physics, all at the University of Cambridge, for their help in writing these articles.
This is a wonderful site and content. All students of math and physics should read this kind of material.
Many thanks! Keep up the good work!!
Finally an article meant to teach.....Thank You Marianne Freiberger
Too many articles just go through the derivation of Schrodinger's Equation.
Question for Marianne:
Is it possible that h/2 is the fundamental quantum size? If we define a new Planck's constant (call it hs) such that hs = h/2, and plug that into the Schroedinger Equation, does that change the usefulness of the equation (or add any other complications to any aspect of physical laws or quantum mechanics)?
I have a reason for asking that, which we can discuss if your answer is no.
Interesting thought, perhaps even 1/4 ? I am interested in discussing this.
Thx for a very fine article. Very clever math! But I've been stumped by magicians who were as clever. The particle must know the location of L before he/she/it can leave x=0, or he/she/or it will not know when to pop back into reality. How does he/she/or it manage that? What was Schrodenger smoking? :>)