Fourier transforms of images

Rachel Thomas Share this page

Fourier transforms of images

Rachel Thomas

The sounds we hear – whether music, speech, or background noise – are the result of vibrations of our ear drum, stimulated by sound waves travelling through the air, created by our headphones, musical instruments, people's voice boxes, or that annoying person behind you in the cinema opening their sweets. These vibrations can be plotted (the intensity, or pressure, of the wave plotted over time) giving us a visual representation of the sound.

Soundwave of a tuning forkSoundwave of human speech

The sound wave from a tuning fork (top), compared with that of human speech (bottom).

The sound wave of the middle A on a tuning fork, is a perfect example of a sine wave, written mathematically as sin(x). The sound wave of speech is more complicated. But any sound wave, indeed any repeating function, can be broken up into a number of sine waves of various frequencies and amplitudes (intensities). This is the result of work that started with the French mathematician, Joseph Fourier, who lived through the French revolution in the eighteenth century. The expression of a sound wave, or any signal varying over time, as the sum of its constituent sine waves, is known as the Fourier transform of that signal. (You can read a more detailed explanation of the maths involved here – the maths is quite complicated but the mathematical ideas involved are lovely!)

The function f varies in time – representing a sound wave. The Fourier transform process takes f and decomposes it into its constituent sine waves, with particular frequencies and amplitudes. The Fourier transform is represented as spikes in the frequency domain, the height of the spike showing the amplitude of the wave of that frequency.

You can also think of an image as a varying function, however, rather than varying in time it varies across the two-dimensional space of the image. In a grey scale digital image the pixels each have a value between 0 and 255 representing the darkness of that pixel. So the darkness, or intensity, of that pixel, is a function of the horizontal and vertical coordinates giving the location of that pixel. You can think of the image as an undulating landscape, with the height of the landscape given by the value of the pixel.

The plus editors, in person and as a surface

A digital photograph of the Plus editors, each pixel has a value between 0 and 255, representing the greyness of that pixel. And on the right, the image function of the same digital photograph is shown, with the grey value u(x, y) plotted as the height of the surface over the (x, y)-plane.

Images can also be expressed as a sum of sine waves, but this time, instead of one-dimensional waves, they are waves that vary in two-dimensions, like ripples on a sheet.

Two-dimensional sine waves are written as

z = a sin(hx+ky)

where x and y give the coordinates for points on the "sheet", z is the height, or intensity, of the wave at that point, a gives the amplitude (the maximum height) of the wave, and h and k give the number of times the wave repeats in the x and y directions respectively (they are the x and y frequencies).

sin(x), sin(2y), sin(x+y)

The waves sin(x), sin(2y) and sin(x+y).

When k=0, the sine wave only fluctuates along the x-axis. When h=0, it only fluctuates along the y-axis. But if both k and h are nonzero, the sine wave moves diagonally across the sheet, with the waves travelling in direction (perpendicular to wave fronts) angled with the slope h/k.

Adding these waves together just involves adding the respective values, or heights, of the waves at each pixel. The waves can constuctively interfere creating a final wave with a higher value at that point. And the waves can destructively interfere and cancel out. If the amplitude of one of the constituent waves is much larger than the others, it will dominate.

Adding two-dimensional sine waves

The waves sin(x)+sin(y), 5sin(x)+sin(y) and sin(x)+5sin(y). You can see how the larger amplitude wave – 5sin(x) in the middle image and 5sin(y) in the image on the right – dominate the resulting wave.

The Fourier transform of an image breaks down the image function (the undulating landscape) into a sum of constituent sine waves. Just as for a sound wave, the Fourier transform is plotted against frequency. But unlike that situation, the frequency space has two dimensions, for the frequencies h and k of the waves in the x and y dimensions. So it is plotted not as a series of spikes, but as an image with (roughly) the same dimensions in pixels as the original image.

Each pixel in the Fourier transform has a coordinate (h,k) representing the contribution of the sine wave with x-frequency h, and y-frequency k in the Fourier transform. The centre point represents the (0,0) wave – a flat plane with no ripples – and its intensity (its brightness in colour in the grey scale) is the average value of the pixels in the image. The points to the left and right of the centre, represent the sine waves that vary along the x-axis, (ie k=0). The brightness of these points represent the intensity of the sine wave with that frequency in the Fourier transform (the intensity is the amplitude of the sine wave, squared). Those vertically above and below the centre point represent those sine waves that vary in y, but remain constant in x (ie h=0). And the other points in the Fourier transform represent the contributions of the diagonal waves.

sin(x) and its Fourier transform

The wave sin(x) represented as a grayscale image, and the Fourier transform of that image.

For example, consider the image above, on the left. This is the two-dimensional wave sin(x) (which we saw earlier) viewed as a grayscale image. Next to it is the Fourier transform of this grayscale image. It has the same dimensions in pixels as the original, and is entirely black except for a few bright pixels at the very centre. If we zoom into the centre of the Fourier transform (which you can see above, on the right) you can see there are exactly three pixels which are not black. One is the bright centre point, with coordinates (0,0), representing the contribution of the (0,0) wave to the image. The bright pixel on either side, with coordinates (1,0) and its reflection (-1,0), represents the contribution of the (1,0) wave (the sine wave in our original image). All the rest of the pixels in the Fourier transform are black, as the original image is exactly described using just the original (1,0) wave.

Some simple Fourier transforms

Top: The wave sin(20x)+sin(10y) and its Fourier transform, showing two pairs of bright pixels (at the coordinates (20,0) and (0,10) and their reflections) representing these contributions of these two waves.
Bottom: The wave sin(100x+50y) and its Fourier transform, showing just the pair of bright pixels at the coordinates (100,50) and its reflection.

The Fourier transforms of simple combinations of waves have only a few bright spots. But for more complex images, such as digital photos, there are many many bright spots in its Fourier transform, as it takes many waves to express the image.

In the Fourier transform of many digital photos we'd normally take, there is often a strong intensity along the x and y axis of the Fourier transform, showing that the sine waves that only vary along these axes play a big part in the final image. This is because there are many horizontal or vertical features and symmetries in the world around us – walls, table tops, even bodies are symmetrical around the vertical axes. You can see this by rotating an image a little (say by 45%). Then its Fourier transform will have a strong intensity along a pair of perpendicular lines that are rotated by the same amount.

Fourier transform of Plus

Plus editors and their Fourier transform, showing a series of contributions of vertical wave represented by bright points along the vertical axis.

Fourier transform of angled Plus

The Plus editors rotated by 45 degrees, and their Fourier transform.

Fourier transforms are incredibly useful tools for the analysis and manipulation of sounds and images. In particular for images, it's the mathematical machinery behind image compression (such as the JPEG format), filtering images and reducing blurring and noise.

The images of 2D sine waves, surfaces and Fourier transforms were made in MATLAB – in case you'd like to try it yourself you can see the commands we used here.

About this article

Rachel Thomas is Editor of Plus.

Read more about...



Very nice introduction. Please replce the range 0 to 254 and 0 to 256 (in the caption) with 0 to 255.
Besides rotation another interesting property that could be mentioned is scaling and its effect on the frequency domain.


thank you very much for this simplification
and please can you refer me to a good source (text book) for more details about how Fourier transform works on images.

See Chapter 4, "Filtering in the Frequency Domain", in "Digital Image Processing", 3ed, Gonzalez and Woods.


Reminds me of this recent Productchart blog post, where they swapped the position and brightness of pixels in greyscale images.


This article was excellent. Without going into heavy details, the author(s) did an excellent job of explaining things from a couple of thousand feet above!



Thank you so much for this clear, informative and well illustrated article! You have plugged a major gap in my understanding of the subject and by far have given the best explanation for this topic for a beginner that I have seen :)


Hello it is really good explanation but I just want to know how Fourier transform can help if one image is normal and other image is scale of first image. And if second image is in rotation can I use Fourier transform to compare two images. And also last question is it gives unique answer for all images in universe.


Thanks for this.
One question about contribution of (0,0) wave in 'The wave sin(x) represented as a grayscale image, and the Fourier transform of that image' photo; does it show the big contribution of 'no changes' in the y axis of image?


This is a really goood article, I am newbie at digital image processing and this gave the on-point explanation.


Sine values result between -1 to 1. So how to saturate values between 0 and 1 so as to represent grey scale values - 0 being dark and 1 being white.
For ex I have this representation f(m,n) = sin(2*pi*u*m/M + 2*pi*v*n/N)


Thank you for your helpful article. I understood Fourier transform of images very well.


Fantastic article! That really help me a lot. By the way, could I translate this in Chinese and public it on a Chinese forum? I will cite this URL and authors in the first paragraph.