# Mathematical Mysteries: Trisecting the Angle

Issue 7Bisecting a given angle using only a pair of compasses and a straight edge is easy. But trisecting it - dividing it into three equal angles - is in most cases impossible. Why?

### Bisecting an angle

If we have a pair of lines meeting at a point O, and we want to bisect the angle between them, here's how we do it.

Bisecting angle AOB using straight edge and compasses.

Put the point of the compass at O and draw a circle (of any radius you like). This is the blue arc in the diagram. The circle will cross the two lines at two points: call these A and B.

Now put the point of the compass at A and draw an arc of a circle, as shown in the diagram. **Without changing the radius at which the compass is set**, move its point to B and draw another arc of a circle. These are the red arcs in the diagram. The point where the two arcs cross, P, can then be joined to O using the straight edge (the green line), and angle POB is half of angle AOB. If the
arcs don't cross, then of course you need to use larger circles!

**prove**that this procedure works, using similar triangles? The ancient Greeks certainly knew how to do this.

### Trisecting an angle

What about trisecting an angle? Why is it so difficult? There are a few special cases of angles for which it can be done - for example, pi/2 radians (90 degrees). For the general case, however, the Greeks couldn't work out how to do it, despite expending vast amounts of energy on the problem.

Trisecting an arbitrary angle can be done if you cheat by using a measuring ruler instead of a plain straight edge (you can find out how in the sci.math FAQ file), or even if you simply draw two little marks on your straight edge. However, to "play by the rules" you aren't allowed any marks on the straight edge at all - it must be completely blank.

The problem of whether trisection could be done in the general case remained a mathematical mystery for millennia - it was only in 1837 that it was eventually proved to be impossible by Pierre Wantzel, a French mathematician and expert on arithmetic. This was a great achievement for a man of 23, who subsequently died at the tragically young age of 33.

So why is it impossible? Pierre showed that the two problems of trisecting an angle and of solving a cubic equation are equivalent. Moreover, he showed that only a very few cubic equations can be solved using the straight-edge-and-compass method - most cannot. He thus deduced that most angles cannot be trisected.

### Footnote : The *real* mystery

Despite the fact that Wantzel's proof means that we now *know* that it's impossible to trisect a general angle, people keep trying. The mathematics department where PASS Maths is based receives quite serious letters every so often from individuals who think they've cracked the problem, offering famous people in the department the opportunity to "buy" the "proof" (sometimes for large
amounts of money!). One such letter even missed out several pages of the "proof" on the grounds of security of the writer's copyright!

Needless to say, all these so-called proofs contain flaws and are worthless. If the writers really wanted to convince anyone that it *is* possible to trisect the angle, their time would be better spent trying to find an error in Wantzel's proof. The real mystery here is why people keep trying to solve the problem in the face of a proof of its impossibility. How would you reply to
them?

## Comments

## Trtisection of the angle: new attempt w.greig@sky.com

Given any angle ABC

Centre the vertex draw an arc to cut the two arms: AB in P BC in S

Join PS

Centre P and radius = PS draw a long seeking arc.

Centre S and radius PS, draw a defining arc to cut the arc centre P inD

Join DB

BD will cut PS at its mid point, E

Centre E and radius EP draw a semi circle to cut PS at P and S.

Centre P and radius EP draw an arc to cut the semi circle centre E at Q

Centre S draw an arc radius ES, to cut the semicircle centre E at R

Join BQ, BR these lines will trisect thew circle.

The development of this technique rests on the extension of the Basic circle equality: equal chords in the same circle subtend equal angles at the circumference.

Given three equal adjacnt angles from the centre of a circle, then the subtending arcs will subtend three equal adjacent angle at any point on any concentric circle.

My paper which is being stolidly ignored by academia, (is in fact copyright) and contains euclidean style proofs leading up to and including the new equal angles proposition. I am willing to share the entire paper with anyone hwo promises to honour the copyright.

## Errors in Post

The section on bisecting an angle with Euclidean compass and straight edge contains errors.

First, you may not draw a circle with an arbitrary radius ("any radius you like"). The only thing you can do with a Euclidean compass is to draw a circle with the center at a known point, and the circumference containing a known point. You cannot just "pick a point," you must construct it. This problem can be avoided by instead drawing the circle with center at the vertex of the angle, and through one of the other two points that are given to define the angle. Restatement: given angle ABC (B the vertex), draw the circle with center B and radius the length of segment AB.

Second, when you lift a Euclidean compass off the paper, it collapses. You cannot just move the compass and keep it set at the same radius.

Mike Ochs

B.A. Mathematics, Univ of Colorado

## By H.S. TANDAVESHWARA dated 19/12/2014

1) Draw AB

2) Draw AC orbitrarily

3) With any radius with compass mark D along AC and E along AB

4) Join DE

Problem :

We have to divide DE to 3 equal parts

1) With D as center mark DF (any distance) arc and with same radius and compass mark FG with F as center and

GH with G as center along AC

2) Join HE

3) With GK as radius mark a circle with E as center . join GL (L is the outer most point in circle)

4) with the top most point L joint G & L with a line

5) Similarly with FN as radius draw a circle with center as I and join MF intersecting DE at J (J is the outer most point in circle)

6) Join AJ, AI

7) Hence angle BAC is divided into 3 parts

By H.S. TANDAVESHWARA dated 19/12/2014

## ANGLE TRISECTION BY H.S. TANDAVESWAR

WITHOUT GIVING ANY PREVIOUS HINTS, YOU HAVE USED POINTS LIKE 'K', 'N', 'I' AND 'M' WHILE SAYING GK, FN AND MF. SIMILARLY WHILE SAYING 'OUTER MOST POINT OF A CIRCLE' YOU SHOULD HAVE BEEN MORE PRECISE AS THERE ARE TWO SUCH POINTS FOR A POINT LYING OUTSIDE THE CIRCLE. I THINK THERE ARE EASIER WAYS OF DIVIDING A LINE INTO 3 EQUAL PARTS.

BUT MOST IMPORTANT: DID YOU MEASURE THE THREE ANGLES CREATED AT 'A'? CAN YOU PROVE THAT THE ANGLES ARE OF EQUAL MEASURE?

## Trisecting an Angle

1) Set up the angle in a circle centring its midpoint

2) Build a triangle using the chord as height

3) Find the Centroid on the chord

...draw your lines and see what may be the real thing

and something you can't prove

## Trisecting an angle

In regards to people tackling a proof trisecting an angle, a case can be made that it isn’t always a worthless endeavor. In my case I am looking at it as a way to keep my mind and thinking active.

The easiest thing to do is to prove that it is impossible to trisect any angle precisely. However there is still the question of is there any method to effectively trisect any angle to an acceptable accuracy in a limited number of steps using only a compass and unmarked straight edge. This is a different issue and is a valid question.

## Trisecting an angle

An angle can be trisected by Euclidean methods in 3 dimensional space.

## Logic Fail

Ha. Logically it is not possible to prove that something is impossible.

## Umm...

Actually the aphorism is that it's not possible to prove a negative (and even that is sometimes wrong). Proving that things are impossible is done all the time... it is the basis, for example, of reductio absurdum or proof by contradiction.

## Prove it.

Prove it.

## Proof of the impossible

Dear anonymous

Mathematicians prove the impossible all the time. One such example is the proff that it is impossible to find the ratio of two integers that equal the square root of two.

touche!

## ummm...

No! That is NOT proving the impossible. Rather, its proving impossible something (huh?). As in, its "un"-proving something.