3 3 8 8 - Solution

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Submitted by plusadmin on 1 March, 2001
March 2001

3 3 8 8 - Solution

The trick to this problem was finding a way to make the most of the two 3's and two 8's that you could use. The answer was:

24 =
  \[ 8\over \displaystyle 3- { 8 \over \displaystyle 3} \]    
To see how this works, start by writing the left hand side as:
  \[ {8 \over 1}\over \displaystyle 3- { 8 \over \displaystyle 3} \]    
When you multiply this out it becomes clear that it is correct.
  \[ {{8\over 1} \over \displaystyle {{9- 8} \over \displaystyle 3}} = {{8 \times 3} \over {(9-8) \times 1}} = {24 \over 1} = 24 \]    
Clever isn't it!

Permalink Submitted by Anonymous (not verified) on 24 February, 2015
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BUT WHY ARE YOU USING 9 IF ITS ONLY 3,3,8,8