Outer space: Blowin' in the wind December 2007 Finding the maximal efficiency We want to calculate the maximum value of windmill efficiency P/P0. Write y for P/P0 and x for V/U. We get y=12(1−x2)(1+x). Differentiating we get dy/dx=12(1−2x−3x2). The maximum occurs when dy/dx=0, in other words when 3x2+2x−1=0. This happens for x0=1/3 and x1=−1. Discounting the negative solution we get a maximal efficiency of 1/2(1−x02)(1+x0)=16/27. Back to main article Read more about... outerspace Log in or register to post comments